What are the solutions for the equation for x squared minus 2x + 2 - 3x - x squared = 0

Put the smaller x value in the first box right in your answer as simple by fractions or whole numbers only
x = blank and blank

1 answer

Let's simplify the equation \(x^2 - 2x + 2 - 3x - x^2 = 0\).

First, combine like terms:

\[ x^2 - x^2 - 2x - 3x + 2 = 0 \]

This simplifies to:

\[ -5x + 2 = 0 \]

Now, isolate \(x\):

\[ -5x = -2 \]

Dividing both sides by -5 gives:

\[ x = \frac{2}{5} \]

Since this is a linear equation, there is only one solution. Thus, the larger \(x\) value does not exist.

Therefore, the answer is:

\(x = \frac{2}{5}\) and blank for the second box.