The force moving the piano down the plane is gravity: mgsinTheta
The retarding forces are friction (mu*mgCosTheta) and the man pushing.
set the retarding force equal to the gravitational force, and you have a.
Work done by mane: his force*distance down the incline
A 290 kg piano slides 4.6 m down a 30° incline and is kept from accelerating by a man who is pushing back on it parallel to the incline. The effective coefficient of kinetic friction is 0.40.
(a) Calculate the force exerted by the man.
N
(b) Calculate the work done by the man on the piano.
J
(c) Calculate the work done by the friction force.
J
(d) What is the work done by the force of gravity?
J
(e) What is the net work done on the piano?
J
5 answers
i got 3029.6 for a and still get wrong
of course it is wrong.
forceman+forcefriction=weight down plane
forceman=mgsinTheta-mu*mg*cosTheta
= 290*9.8(sin30-.4*cos30)
Surely you can see that is not 3000N
forceman+forcefriction=weight down plane
forceman=mgsinTheta-mu*mg*cosTheta
= 290*9.8(sin30-.4*cos30)
Surely you can see that is not 3000N
its incorrect
F = (290*9.8*sin30) - (290*9.8*cos30*0.40) = 436.5 N.
Is this the correct answer?
Is this the correct answer?
1 answer