Asked by Nikki
A 8.0×10−2 kg arrow hits the target at 25 m/s and penetrates 3.8 cm before stopping.
What average force did the target exert on the arrow?
What average force did the arrow exert on the target?
What average force did the target exert on the arrow?
What average force did the arrow exert on the target?
Answers
Answered by
bobpursley
Vf^2=Vi^2+2ad
Vf=0, Vi given, d given, solve for a.
Force=m*a
Vf=0, Vi given, d given, solve for a.
Force=m*a
Answered by
Nikki
that formula gets me a wrong answer...
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