Question
Determine the solution to the system of equations below. Enter your answer as an (x,y) ordered pair.
y=-1/2x+3
y=5/2x-3
y=-1/2x+3
y=5/2x-3
Answers
Answered by
GPT-4o mini
To determine the solution to the given system of equations:
1. \( y = -\frac{1}{2}x + 3 \)
2. \( y = \frac{5}{2}x - 3 \)
We can set the two equations equal to each other because they both equal \( y \):
\[
-\frac{1}{2}x + 3 = \frac{5}{2}x - 3
\]
Now, we will solve for \( x \):
1. Add \(\frac{1}{2}x\) to both sides:
\[
3 = \frac{5}{2}x + \frac{1}{2}x - 3
\]
2. The left side stays the same, and we can combine terms on the right side. Notice that \(\frac{5}{2}x + \frac{1}{2}x\) can be combined since they have the same denominator:
\[
3 = ( \frac{5}{2} + \frac{1}{2} ) x - 3
\]
\[
3 = \frac{6}{2}x - 3
\]
\[
3 = 3x - 3
\]
3. Now add 3 to both sides:
\[
3 + 3 = 3x
\]
\[
6 = 3x
\]
4. Divide both sides by 3:
\[
x = 2
\]
Now that we have \( x \), we can substitute it back into one of the original equations to find \( y \). Let's use the first equation:
\[
y = -\frac{1}{2}(2) + 3
\]
\[
y = -1 + 3
\]
\[
y = 2
\]
Thus, the solution to the system of equations is:
\[
\boxed{(2, 2)}
\]
1. \( y = -\frac{1}{2}x + 3 \)
2. \( y = \frac{5}{2}x - 3 \)
We can set the two equations equal to each other because they both equal \( y \):
\[
-\frac{1}{2}x + 3 = \frac{5}{2}x - 3
\]
Now, we will solve for \( x \):
1. Add \(\frac{1}{2}x\) to both sides:
\[
3 = \frac{5}{2}x + \frac{1}{2}x - 3
\]
2. The left side stays the same, and we can combine terms on the right side. Notice that \(\frac{5}{2}x + \frac{1}{2}x\) can be combined since they have the same denominator:
\[
3 = ( \frac{5}{2} + \frac{1}{2} ) x - 3
\]
\[
3 = \frac{6}{2}x - 3
\]
\[
3 = 3x - 3
\]
3. Now add 3 to both sides:
\[
3 + 3 = 3x
\]
\[
6 = 3x
\]
4. Divide both sides by 3:
\[
x = 2
\]
Now that we have \( x \), we can substitute it back into one of the original equations to find \( y \). Let's use the first equation:
\[
y = -\frac{1}{2}(2) + 3
\]
\[
y = -1 + 3
\]
\[
y = 2
\]
Thus, the solution to the system of equations is:
\[
\boxed{(2, 2)}
\]