Factor completely.

50m3–25m2+44m–22

1 answer

To factor the polynomial \(50m^3 - 25m^2 + 44m - 22\), we can start by grouping the terms.

  1. Grouping the polynomial: \[ (50m^3 - 25m^2) + (44m - 22) \]

  2. Factoring out the common factors from each group:

    • From the first group, \(50m^3 - 25m^2\), we can factor out \(25m^2\): \[ 25m^2(2m - 1) \]
    • From the second group, \(44m - 22\), we can factor out \(22\): \[ 22(2m - 1) \]
  3. Now we rewrite our original expression: \[ 25m^2(2m - 1) + 22(2m - 1) \]

  4. Notice that \( (2m - 1) \) is a common factor: \[ (2m - 1)(25m^2 + 22) \]

  5. Now we have factored the expression into: \[ (2m - 1)(25m^2 + 22) \]

  6. Checking for further factorization:

    • \(25m^2 + 22\) does not factor further over the reals (since its roots involve complex numbers).

Thus, the completely factored form of the polynomial \(50m^3 - 25m^2 + 44m - 22\) is: \[ \boxed{(2m - 1)(25m^2 + 22)} \]