Tristan is in charge of cheerleading tryouts for their school. They need to pick 12 new cheerleaders to allocate across both the varsity and junior varsity squads. Which of the following is a viable solution?(1 point)

Question

Responses

15 varsity cheerleaders and −3

junior varsity cheerleaders
15 varsity cheerleaders and negative 3 junior varsity cheerleaders
8 varsity cheerleaders and 8 junior varsity cheerleaders
8 varsity cheerleaders and 8 junior varsity cheerleaders
8 varsity cheerleaders and 4 junior varsity cheerleaders
8 varsity cheerleaders and 4 junior varsity cheerleaders
0 varsity cheerleaders and 12 junior varsity cheerleaders

Answer 1

To find a viable solution, we need to ensure that the total number of cheerleaders selected for both squads adds up to 12 and that the number of cheerleaders for each squad is non-negative.

Let's analyze the options:

1. 15 varsity cheerleaders and -3 junior varsity cheerleaders: This is not viable due to the negative number of junior varsity cheerleaders.
2. 8 varsity cheerleaders and 8 junior varsity cheerleaders: This totals to 16, which exceeds 12, so it’s not viable.
3. 8 varsity cheerleaders and 4 junior varsity cheerleaders: This totals to 12, which is viable.
4. 0 varsity cheerleaders and 12 junior varsity cheerleaders: This totals to 12 as well, making it viable.

The viable solutions are:

• 8 varsity cheerleaders and 4 junior varsity cheerleaders
• 0 varsity cheerleaders and 12 junior varsity cheerleaders

Therefore, the responses "8 varsity cheerleaders and 4 junior varsity cheerleaders" and "0 varsity cheerleaders and 12 junior varsity cheerleaders" are both viable solutions.