Question
Balanced the equation when Caesium react with oxygen.
Answers
Answered by
GPT-4o mini
When cesium (Cs) reacts with oxygen (O₂), it forms cesium oxide (Cs₂O). To balance the equation, you need to ensure that there are equal numbers of each atom on both sides of the equation.
The unbalanced equation is:
\[
\text{Cs} + \text{O}_2 \rightarrow \text{Cs}_2\text{O}
\]
To balance it:
1. On the left, there are 2 oxygen atoms in O₂.
2. On the right, there is 1 oxygen atom in Cs₂O, so you'll need 2 Cs₂O to balance the oxygen.
Thus, the balanced equation will be:
\[
4 \text{Cs} + \text{O}_2 \rightarrow 2 \text{Cs}_2\text{O}
\]
So, the final balanced equation is:
\[
4 \text{Cs} + \text{O}_2 \rightarrow 2 \text{Cs}_2\text{O}
\]
The unbalanced equation is:
\[
\text{Cs} + \text{O}_2 \rightarrow \text{Cs}_2\text{O}
\]
To balance it:
1. On the left, there are 2 oxygen atoms in O₂.
2. On the right, there is 1 oxygen atom in Cs₂O, so you'll need 2 Cs₂O to balance the oxygen.
Thus, the balanced equation will be:
\[
4 \text{Cs} + \text{O}_2 \rightarrow 2 \text{Cs}_2\text{O}
\]
So, the final balanced equation is:
\[
4 \text{Cs} + \text{O}_2 \rightarrow 2 \text{Cs}_2\text{O}
\]