Asked by Lori
Working of a problem--I have found the mean, variance and the standard deviation from the following info:
The probability that a cellular phone company Kiosk sells X number of new phone contracts per day is shown below----
X=4, 5, 6, 8, 10
P(X)=0.4, 0.3, 0.1, 0.15, .0.05
Mean=5.4
Variance=2.94
Standard deviation=1.71
Cool with this--question--what is the probability that they will sell 6 or more contracts three days in a row??
How do I set this up?
The probability that a cellular phone company Kiosk sells X number of new phone contracts per day is shown below----
X=4, 5, 6, 8, 10
P(X)=0.4, 0.3, 0.1, 0.15, .0.05
Mean=5.4
Variance=2.94
Standard deviation=1.71
Cool with this--question--what is the probability that they will sell 6 or more contracts three days in a row??
How do I set this up?
Answers
Answered by
Lori
Sorry--I guess I was using the logic that with so many people using this that my questions may have been overlooked. I have had a couple questions that haven't been addressed this week. Again, sorry for the inconvenience. I truly appreciate the help.
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