Use the image to answer the question.

An illustration shows a bar graph with four bars extending vertically from the x-axis. The horizontal axis ranges from 10 to 13 in increments of 1 and the vertical axis ranges from 0 to 5 in increments of 1. The bar placed at 10 on the x-axis extends to 2 on the y-axis. The bar placed at 11 on the x-axis extends to 4 on the y-axis. The bar placed at 12 on the x-axis extends to 4 on the y-axis. The bar placed at 13 on the x-axis extends to 2 on the y-axis.

What are the values of the mean, median, and spread for the dataset shown in the bar graph?

(2 points)
The mean =
.
The median =
.
The spread =
.

1 answer

To calculate the mean, median, and spread for the dataset represented in the bar graph, we first need to extract the data points based on the information provided:

  • At x = 10, the height is 2 → Dataset: 10, 10
  • At x = 11, the height is 4 → Dataset: 11, 11, 11, 11
  • At x = 12, the height is 4 → Dataset: 12, 12, 12, 12
  • At x = 13, the height is 2 → Dataset: 13, 13

Combining these, the complete dataset is: \[ [10, 10, 11, 11, 11, 11, 12, 12, 12, 12, 13, 13] \]

1. Mean:

To find the mean, we sum all values and divide by the number of values.

Sum = \( 10 + 10 + 11 + 11 + 11 + 11 + 12 + 12 + 12 + 12 + 13 + 13 = 102 + 114 + 124 + 132 = 20 + 44 + 48 + 26 = 138 \)

Number of values = 12

Mean = \( \frac{138}{12} = 11.5 \)

2. Median:

To find the median, we need to arrange the dataset in ascending order (which it already is):

\[ [10, 10, 11, 11, 11, 11, 12, 12, 12, 12, 13, 13] \]

Since there are 12 values (even number), the median is the average of the 6th and 7th values.

6th value = 11 7th value = 12

Median = \( \frac{11 + 12}{2} = \frac{23}{2} = 11.5 \)

3. Spread:

The spread can be calculated as the range of the data, which is the difference between the maximum and minimum values.

Minimum value = 10 Maximum value = 13

Spread = Maximum - Minimum = \( 13 - 10 = 3 \)

Summary of Results:

  • The mean = 11.5
  • The median = 11.5
  • The spread = 3

Thus, we have:

  • Mean = 11.5
  • Median = 11.5
  • Spread = 3