To complete the table using the equation \( y = 4x \), we can substitute the values of \( x \) into the equation to find the corresponding \( y \) values.
Here’s the completed table:
| x | y | |---|----| | 0 | 0 | (since \( y = 4 \cdot 0 = 0 \)) | | 1 | 4 | (since \( y = 4 \cdot 1 = 4 \)) | | 2 | 8 | (since \( y = 4 \cdot 2 = 8 \)) | | 3 | 12 | (since \( y = 4 \cdot 3 = 12 \)) |
So, the completed table looks like this:
| x | y | |---|----| | 0 | 0 | | 1 | 4 | | 2 | 8 | | 3 | 12 |