To complete the table using the equation \( y = x + 3 \), we can substitute the values of \( x \) into the equation to find the corresponding values of \( y \).
Here’s the completed table:
\[ \begin{array}{|c|c|} \hline x & y \ \hline 0 & 3 \ 1 & 4 \ 2 & 5 \ 3 & 6 \ \hline \end{array} \]
So for each value of \( x \):
- When \( x = 0 \), \( y = 0 + 3 = 3 \)
- When \( x = 1 \), \( y = 1 + 3 = 4 \)
- When \( x = 2 \), \( y = 2 + 3 = 5 \)
- When \( x = 3 \), \( y = 3 + 3 = 6 \)