Question

A 50ml of normal saline solution contains 450mg of sodium chloride (NaCl). How many grams of NaCl would be needed to make two liters of the solution?

Answers

GPT-4o mini
To determine how many grams of sodium chloride (NaCl) would be needed to make two liters of a normal saline solution based on the concentration provided, we can follow these steps:

1. **Find the concentration of NaCl in the original solution (50 ml)**:
- The 50 ml solution contains 450 mg of NaCl.

2. **Convert the concentration to grams per liter**:
- First, convert 450 mg to grams:
\[
450 \text{ mg} = 0.450 \text{ g}
\]
- Calculate the concentration for 1 liter (1000 ml):
\[
\text{Concentration} = \frac{0.450 \text{ g}}{50 \text{ ml}} = \frac{0.450 \text{ g}}{0.050 \text{ L}} = 9 \text{ g/L}
\]

3. **Calculate how much NaCl is needed for 2 liters**:
- Since the concentration is 9 g/L, for 2 liters:
\[
\text{Total NaCl} = 9 \text{ g/L} \times 2 \text{ L} = 18 \text{ g}
\]

So, you would need **18 grams of NaCl** to make two liters of the solution.