A 50ml of normal saline solution contains 450mg of sodium chloride (NaCl). How many grams of NaCl would be needed to make two liters of the solution?

1 answer

To determine how many grams of sodium chloride (NaCl) would be needed to make two liters of a normal saline solution based on the concentration provided, we can follow these steps:

  1. Find the concentration of NaCl in the original solution (50 ml):

    • The 50 ml solution contains 450 mg of NaCl.
  2. Convert the concentration to grams per liter:

    • First, convert 450 mg to grams: \[ 450 \text{ mg} = 0.450 \text{ g} \]
    • Calculate the concentration for 1 liter (1000 ml): \[ \text{Concentration} = \frac{0.450 \text{ g}}{50 \text{ ml}} = \frac{0.450 \text{ g}}{0.050 \text{ L}} = 9 \text{ g/L} \]
  3. Calculate how much NaCl is needed for 2 liters:

    • Since the concentration is 9 g/L, for 2 liters: \[ \text{Total NaCl} = 9 \text{ g/L} \times 2 \text{ L} = 18 \text{ g} \]

So, you would need 18 grams of NaCl to make two liters of the solution.