Question
What is the area of the irregular figure below?
A figure can be broken into a parallelogram and triangle. The parallelogram has a base of 22 centimeters and height of 10 centimeters. The triangle has a base of 14 centimeters and height of 10 centimeters.
290 Centimeters squared
360 Centimeters squared
3,960 Centimeters squared
7,920 Centimeters squared
A figure can be broken into a parallelogram and triangle. The parallelogram has a base of 22 centimeters and height of 10 centimeters. The triangle has a base of 14 centimeters and height of 10 centimeters.
290 Centimeters squared
360 Centimeters squared
3,960 Centimeters squared
7,920 Centimeters squared
Answers
GPT-4o mini
To find the area of the irregular figure, we need to calculate the area of both the parallelogram and the triangle and then add those areas together.
**Step 1: Area of the Parallelogram**
The formula for the area of a parallelogram is:
\[
\text{Area} = \text{base} \times \text{height}
\]
Given the base of the parallelogram is 22 cm and the height is 10 cm:
\[
\text{Area}_{\text{parallelogram}} = 22 \, \text{cm} \times 10 \, \text{cm} = 220 \, \text{cm}^2
\]
**Step 2: Area of the Triangle**
The formula for the area of a triangle is:
\[
\text{Area} = \frac{1}{2} \times \text{base} \times \text{height}
\]
Given the base of the triangle is 14 cm and the height is 10 cm:
\[
\text{Area}_{\text{triangle}} = \frac{1}{2} \times 14 \, \text{cm} \times 10 \, \text{cm} = 70 \, \text{cm}^2
\]
**Step 3: Total Area of the Irregular Figure**
Now, we add the area of the parallelogram and the area of the triangle together:
\[
\text{Total Area} = \text{Area}_{\text{parallelogram}} + \text{Area}_{\text{triangle}} = 220 \, \text{cm}^2 + 70 \, \text{cm}^2 = 290 \, \text{cm}^2
\]
Thus, the area of the irregular figure is:
\[
\boxed{290} \, \text{cm}^2
\]
**Step 1: Area of the Parallelogram**
The formula for the area of a parallelogram is:
\[
\text{Area} = \text{base} \times \text{height}
\]
Given the base of the parallelogram is 22 cm and the height is 10 cm:
\[
\text{Area}_{\text{parallelogram}} = 22 \, \text{cm} \times 10 \, \text{cm} = 220 \, \text{cm}^2
\]
**Step 2: Area of the Triangle**
The formula for the area of a triangle is:
\[
\text{Area} = \frac{1}{2} \times \text{base} \times \text{height}
\]
Given the base of the triangle is 14 cm and the height is 10 cm:
\[
\text{Area}_{\text{triangle}} = \frac{1}{2} \times 14 \, \text{cm} \times 10 \, \text{cm} = 70 \, \text{cm}^2
\]
**Step 3: Total Area of the Irregular Figure**
Now, we add the area of the parallelogram and the area of the triangle together:
\[
\text{Total Area} = \text{Area}_{\text{parallelogram}} + \text{Area}_{\text{triangle}} = 220 \, \text{cm}^2 + 70 \, \text{cm}^2 = 290 \, \text{cm}^2
\]
Thus, the area of the irregular figure is:
\[
\boxed{290} \, \text{cm}^2
\]