Question
What is the width of a block with a density of 8 g/cm3
, a mass of 20 kilograms, a length of 5 centimeters, and a height of 10 centimeters?(1 point)
Responses
50 cm
50 cm
5 cm
5 cm
3.2 cm
3.2 cm
25 cm
, a mass of 20 kilograms, a length of 5 centimeters, and a height of 10 centimeters?(1 point)
Responses
50 cm
50 cm
5 cm
5 cm
3.2 cm
3.2 cm
25 cm
Answers
GPT-4o mini
To find the width of the block, we can use the formula for mass, density, and volume:
\[
\text{Density} = \frac{\text{Mass}}{\text{Volume}}
\]
We know the density and the mass. First, we need to convert the mass from kilograms to grams:
\[
20 \text{ kg} = 20,000 \text{ g}
\]
Next, we can rearrange the density formula to find the volume:
\[
\text{Volume} = \frac{\text{Mass}}{\text{Density}} = \frac{20000 \text{ g}}{8 \text{ g/cm}^3} = 2500 \text{ cm}^3
\]
Now, the volume of a block can also be calculated with the formula:
\[
\text{Volume} = \text{Length} \times \text{Width} \times \text{Height}
\]
We know the length and height. Let \( W \) be the width:
\[
2500 \text{ cm}^3 = 5 \text{ cm} \times W \times 10 \text{ cm}
\]
Now, solving for \( W \):
\[
2500 = 50W
\]
\[
W = \frac{2500}{50} = 50 \text{ cm}
\]
Thus, the width of the block is **50 cm**.
\[
\text{Density} = \frac{\text{Mass}}{\text{Volume}}
\]
We know the density and the mass. First, we need to convert the mass from kilograms to grams:
\[
20 \text{ kg} = 20,000 \text{ g}
\]
Next, we can rearrange the density formula to find the volume:
\[
\text{Volume} = \frac{\text{Mass}}{\text{Density}} = \frac{20000 \text{ g}}{8 \text{ g/cm}^3} = 2500 \text{ cm}^3
\]
Now, the volume of a block can also be calculated with the formula:
\[
\text{Volume} = \text{Length} \times \text{Width} \times \text{Height}
\]
We know the length and height. Let \( W \) be the width:
\[
2500 \text{ cm}^3 = 5 \text{ cm} \times W \times 10 \text{ cm}
\]
Now, solving for \( W \):
\[
2500 = 50W
\]
\[
W = \frac{2500}{50} = 50 \text{ cm}
\]
Thus, the width of the block is **50 cm**.