A wildlife manager determines there are approximately 300 deer in a certain state park. The population is growing at a rate of 4% per year.

Which exponential equation models this situation?

(1 point)
Responses

y=300(0.96)x
y is equal to 300 times 0 point 9 6 to the x th power - no response given

y=300+1.04x
y is equal to 300 plus 1 point 0 4 x - no response given

y=300(1.04)x
y is equal to 300 times 1 point 0 4 to the x th power - correct

y=200(0.07)x
y is equal to 200 times 0 point 0 7 to the x th power - no response given
Question 2
Use the equation you selected above to complete the following statement. Round your answer to the nearest whole deer. (1 point)
After 6 years, there will be
deer in the park.

1 answer

The correct exponential equation for the deer population growing at a rate of 4% per year is:

\[ y = 300(1.04)^x \]

Now, to find the population after 6 years, we substitute \( x = 6 \) into the equation:

\[ y = 300(1.04)^6 \]

Calculating \( (1.04)^6 \):

\[ (1.04)^6 \approx 1.265319 \]

Now multiply this by 300:

\[ y \approx 300 \times 1.265319 \approx 379.5957 \]

Rounding to the nearest whole number, we get:

\[ y \approx 380 \]

So, after 6 years, there will be approximately 380 deer in the park.