Question

If you toss two coins simultaneously, what is the probability of getting exactly one head? Write your answer in the simplest form of fraction.(1 point)
Responses

14
Start Fraction 1 over 4 End Fraction

28
Start Fraction 2 over 8 End Fraction

12
Start Fraction 1 over 2 End Fraction

18

Answer 1

To find the probability of getting exactly one head when tossing two coins, let's first consider the possible outcomes:

1. Heads, Heads (HH)
2. Heads, Tails (HT)
3. Tails, Heads (TH)
4. Tails, Tails (TT)

Out of these four outcomes, the outcomes that have exactly one head are:

- Heads, Tails (HT)
- Tails, Heads (TH)

This gives us 2 favorable outcomes.

The total number of possible outcomes is 4. Therefore, the probability of getting exactly one head is:

\[
\text{Probability} = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} = \frac{2}{4} = \frac{1}{2}
\]

Thus, the probability of getting exactly one head when tossing two coins is:

\(\frac{1}{2}\)

So the correct response is:

**12 Start Fraction 1 over 2 End Fraction**