When a fair six-sided number cube is thrown, what is the probability of getting a number greater than 4? The cube faces are numbered 1 through 6. Express your answer in simplest form of the fraction.(1 point)

Responses

2
2

12
Start Fraction 1 over 2 End Fraction

36
Start Fraction 3 over 6 End Fraction

13

1 answer

To determine the probability of rolling a number greater than 4 on a fair six-sided die, we first identify the outcomes of interest.

The numbers greater than 4 on a six-sided die (1, 2, 3, 4, 5, 6) are:

  • 5
  • 6

This means there are 2 favorable outcomes (5 and 6).

The total number of possible outcomes when throwing the die is 6 (the numbers 1, 2, 3, 4, 5, and 6).

The probability can be calculated with the formula:

\[ \text{Probability} = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} = \frac{2}{6} \]

Now, we simplify \(\frac{2}{6}\):

\[ \frac{2}{6} = \frac{1}{3} \]

So the probability of rolling a number greater than 4 is:

\(\frac{1}{3}\)

None of the given answer choices match \(\frac{1}{3}\), which indicates an error in the provided options. The correct probability is \(\frac{1}{3}\).