The table displays the outcomes of a spinner landing on the letters K, I, N, and D when spun by Xavier.

Question

Outcome K I N D
Frequency 120 140 105 135
A spinner is divided into 4 sections labeled as K
, I
, N
, D
. Xavier reproduced the wheel and uses a computer to simulate the outcomes of 500 spins. What is the approximate probability that the spinner will stop on a consonant on the next spin?

(1 point)
Responses

0.72
0.72

0.45
0.45

0.28
0.28

0.24

Answer 1

To find the probability of the spinner stopping on a consonant, we first identify the consonants in the given letters K, I, N, and D. The consonants are K, N, and D, while I is a vowel.

Next, we calculate the total frequency of all outcomes, which is:

\[ 120 , (K) + 140 , (I) + 105 , (N) + 135 , (D) = 500 \]

The total number of spins is 500, which matches what Xavier is simulating.

Now, we find the frequency of the consonants:

• K: 120
• N: 105
• D: 135

Next, we sum the frequencies of the consonants:

\[ 120 + 105 + 135 = 360 \]

Now we can calculate the probability of landing on a consonant:

\[ \text{Probability of consonants} = \frac{\text{Number of consonant outcomes}}{\text{Total outcomes}} = \frac{360}{500} \]

Now we perform the division:

\[ \frac{360}{500} = 0.72 \]

Thus, the approximate probability that the spinner will stop on a consonant on the next spin is 0.72.

So the correct response is:

0.72