In a certain book series, the average number of pages in each book is 315 pages with a standard deviation of 23.

Ayna recently finished a book in the series that was 330 pages long. Calculate the z-score of this book to the nearest hundredth.

(1 point)
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1 answer

To calculate the z-score for the book that Ayna recently finished, you can use the following formula:

\[ z = \frac{(X - \mu)}{\sigma} \]

Where:

  • \(X\) is the value (the number of pages in Ayna's book).
  • \(\mu\) is the mean (average number of pages in the series).
  • \(\sigma\) is the standard deviation.

Given:

  • \(X = 330\) pages (the book Ayna finished)
  • \(\mu = 315\) pages (average number of pages)
  • \(\sigma = 23\) pages (standard deviation)

Now, plug in the values:

\[ z = \frac{(330 - 315)}{23} = \frac{15}{23} \approx 0.652173913 \]

Now, rounding to the nearest hundredth:

\[ z \approx 0.65 \]

Thus, the z-score of the book is approximately \(z = 0.65\).