Question
You rolled a six-sided dice 6 times and you rolled two 5's in your 6 rolls. Does the experimental probability match the theoretical probability of rolling a 5?
Group of answer choices
No
Yes
You would need more rolls to find out
Not enough info
Group of answer choices
No
Yes
You would need more rolls to find out
Not enough info
Answers
GPT-4o mini
To determine if the experimental probability matches the theoretical probability of rolling a 5 on a six-sided die, we need to first look at the theoretical probability.
The theoretical probability of rolling a 5 on a six-sided die is given by:
\[
P(rolling\ a\ 5) = \frac{\text{Number of favorable outcomes}}{\text{Total outcomes}} = \frac{1}{6}
\]
In your experiment, you rolled the die 6 times and rolled two 5's. Hence, the experimental probability of rolling a 5 is:
\[
P_{experimental} = \frac{\text{Number of times 5 was rolled}}{\text{Total rolls}} = \frac{2}{6} = \frac{1}{3}
\]
Now, we compare the experimental probability \(\frac{1}{3}\) with the theoretical probability \(\frac{1}{6}\).
Since \(\frac{1}{3} \neq \frac{1}{6}\), the experimental probability does not match the theoretical probability.
Therefore, the correct answer is:
**No**
The theoretical probability of rolling a 5 on a six-sided die is given by:
\[
P(rolling\ a\ 5) = \frac{\text{Number of favorable outcomes}}{\text{Total outcomes}} = \frac{1}{6}
\]
In your experiment, you rolled the die 6 times and rolled two 5's. Hence, the experimental probability of rolling a 5 is:
\[
P_{experimental} = \frac{\text{Number of times 5 was rolled}}{\text{Total rolls}} = \frac{2}{6} = \frac{1}{3}
\]
Now, we compare the experimental probability \(\frac{1}{3}\) with the theoretical probability \(\frac{1}{6}\).
Since \(\frac{1}{3} \neq \frac{1}{6}\), the experimental probability does not match the theoretical probability.
Therefore, the correct answer is:
**No**