Question
If you have 1.14 mol of CO2 at a pressure of 3.4 atm and a temperature of 100oC, what will the volume be?
Responses
118.7 Liters
118.7 Liters
19.6 Liters
19.6 Liters
10.27 Liters
10.27 Liters
0.0973 Liters
Responses
118.7 Liters
118.7 Liters
19.6 Liters
19.6 Liters
10.27 Liters
10.27 Liters
0.0973 Liters
Answers
GPT-4o mini
To find the volume of carbon dioxide (CO₂) given the number of moles, pressure, and temperature, we can use the Ideal Gas Law equation:
\[
PV = nRT
\]
Where:
- \( P \) = pressure in atm
- \( V \) = volume in liters
- \( n \) = number of moles
- \( R \) = ideal gas constant (\( 0.0821 \, \text{L} \cdot \text{atm} / \text{K} \cdot \text{mol} \))
- \( T \) = temperature in Kelvin
### Step 1: Convert temperature to Kelvin
The temperature must be in Kelvin for the Ideal Gas Law:
\[
T(K) = T(°C) + 273.15 = 100°C + 273.15 = 373.15 \, K
\]
### Step 2: Plug in values into the Ideal Gas Law
We are given:
- \( n = 1.14 \, \text{mol} \)
- \( P = 3.4 \, \text{atm} \)
- \( R = 0.0821 \, \text{L} \cdot \text{atm} / \text{K} \cdot \text{mol} \)
- \( T = 373.15 \, K \)
Now we can rearrange the equation to solve for \( V \):
\[
V = \frac{nRT}{P}
\]
Substituting in the values:
\[
V = \frac{(1.14 \, \text{mol}) \times (0.0821 \, \text{L} \cdot \text{atm} / \text{K} \cdot \text{mol}) \times (373.15 \, K)}{3.4 \, \text{atm}}
\]
### Step 3: Calculate
Now let's compute the value step by step:
- Calculate the numerator:
\[
1.14 \times 0.0821 \times 373.15 \approx 35.052
\]
- Calculate the volume:
\[
V = \frac{35.052}{3.4} \approx 10.27 \, \text{L}
\]
Therefore, the volume of CO₂ under the given conditions is approximately **10.27 Liters**.
### Conclusion
The correct answer is **10.27 Liters**.
\[
PV = nRT
\]
Where:
- \( P \) = pressure in atm
- \( V \) = volume in liters
- \( n \) = number of moles
- \( R \) = ideal gas constant (\( 0.0821 \, \text{L} \cdot \text{atm} / \text{K} \cdot \text{mol} \))
- \( T \) = temperature in Kelvin
### Step 1: Convert temperature to Kelvin
The temperature must be in Kelvin for the Ideal Gas Law:
\[
T(K) = T(°C) + 273.15 = 100°C + 273.15 = 373.15 \, K
\]
### Step 2: Plug in values into the Ideal Gas Law
We are given:
- \( n = 1.14 \, \text{mol} \)
- \( P = 3.4 \, \text{atm} \)
- \( R = 0.0821 \, \text{L} \cdot \text{atm} / \text{K} \cdot \text{mol} \)
- \( T = 373.15 \, K \)
Now we can rearrange the equation to solve for \( V \):
\[
V = \frac{nRT}{P}
\]
Substituting in the values:
\[
V = \frac{(1.14 \, \text{mol}) \times (0.0821 \, \text{L} \cdot \text{atm} / \text{K} \cdot \text{mol}) \times (373.15 \, K)}{3.4 \, \text{atm}}
\]
### Step 3: Calculate
Now let's compute the value step by step:
- Calculate the numerator:
\[
1.14 \times 0.0821 \times 373.15 \approx 35.052
\]
- Calculate the volume:
\[
V = \frac{35.052}{3.4} \approx 10.27 \, \text{L}
\]
Therefore, the volume of CO₂ under the given conditions is approximately **10.27 Liters**.
### Conclusion
The correct answer is **10.27 Liters**.