Question
If h = 12 units and r = 4 units, what is the volume of the cone shown above?
Use 3.14 for
.
A.
602.88 cubic units
B.
50.24 cubic units
C.
200.96 cubic units
D.
12.56 cubic units
Answers
GPT-4o mini
To find the volume of a cone, you can use the formula:
\[
V = \frac{1}{3} \pi r^2 h
\]
Where:
- \( V \) is the volume,
- \( r \) is the radius,
- \( h \) is the height,
- \( \pi \) is approximately 3.14.
Given:
- \( h = 12 \) units,
- \( r = 4 \) units.
Now, substitute the values into the volume formula:
\[
V = \frac{1}{3} \times 3.14 \times (4^2) \times 12
\]
Calculating \( 4^2 \):
\[
4^2 = 16
\]
Now plug it into the volume formula:
\[
V = \frac{1}{3} \times 3.14 \times 16 \times 12
\]
Calculating \( 16 \times 12 \):
\[
16 \times 12 = 192
\]
Now substitute it back into the equation:
\[
V = \frac{1}{3} \times 3.14 \times 192
\]
Calculating \( 3.14 \times 192 \):
\[
3.14 \times 192 = 602.88
\]
Now, divide by 3:
\[
V = \frac{602.88}{3} = 200.96
\]
Thus, the volume of the cone is:
\[
\boxed{200.96} \text{ cubic units}
\]
\[
V = \frac{1}{3} \pi r^2 h
\]
Where:
- \( V \) is the volume,
- \( r \) is the radius,
- \( h \) is the height,
- \( \pi \) is approximately 3.14.
Given:
- \( h = 12 \) units,
- \( r = 4 \) units.
Now, substitute the values into the volume formula:
\[
V = \frac{1}{3} \times 3.14 \times (4^2) \times 12
\]
Calculating \( 4^2 \):
\[
4^2 = 16
\]
Now plug it into the volume formula:
\[
V = \frac{1}{3} \times 3.14 \times 16 \times 12
\]
Calculating \( 16 \times 12 \):
\[
16 \times 12 = 192
\]
Now substitute it back into the equation:
\[
V = \frac{1}{3} \times 3.14 \times 192
\]
Calculating \( 3.14 \times 192 \):
\[
3.14 \times 192 = 602.88
\]
Now, divide by 3:
\[
V = \frac{602.88}{3} = 200.96
\]
Thus, the volume of the cone is:
\[
\boxed{200.96} \text{ cubic units}
\]