Question

Water is leaking out of a container. At 2:30 p.m., there are 29 pints of water in the container. At 4 p.m., there are 23 pints of water in the container.

If the water continues leaking out of the container at the same rate, how much water will be in the container at 6:30 p.m.?
A.
13 pints
B.
21 pints
C.
18 pints
D.
33 pints

Answer 1

To determine how much water will be in the container at 6:30 p.m., we first need to calculate the rate at which the water is leaking.

1. **Calculate the time between 2:30 p.m. and 4:00 p.m.**:
- From 2:30 p.m. to 4:00 p.m. is 1 hour and 30 minutes, or 1.5 hours.

2. **Determine the change in water volume**:
- At 2:30 p.m., there are 29 pints.
- At 4:00 p.m., there are 23 pints.
- The change in volume is \(29 - 23 = 6\) pints.

3. **Calculate the rate of leakage**:
- The rate of leakage is \( \frac{6 \text{ pints}}{1.5 \text{ hours}} = 4 \text{ pints per hour}\).

4. **Determine the time from 4:00 p.m. to 6:30 p.m.**:
- From 4:00 p.m. to 6:30 p.m. is 2 hours and 30 minutes, or 2.5 hours.

5. **Calculate the amount of water leaked from 4:00 p.m. to 6:30 p.m.**:
- Water leaked in that time is \(4 \text{ pints/hour} \times 2.5 \text{ hours} = 10 \text{ pints}\).

6. **Calculate the remaining water at 6:30 p.m.**:
- At 4:00 p.m., there are 23 pints.
- After 10 pints leak out, there will be \(23 - 10 = 13\) pints left.

Therefore, at 6:30 p.m., there will be **13 pints** of water remaining in the container.

The answer is **A. 13 pints**.