Question

.A standard number cube with the numbers 1, 2, 3, 4, 5, and 6 is rolled one time. Drag the probability of each event occurring to the correct location on the probability scale.



rolling a number greater than 1
rolling a number less than or equal to 6
rolling a 6
rolling an odd number
olling a zero

Answer 1

Let's examine each of the events based on the possible outcomes when rolling a standard number cube (also known as a six-sided die) with faces labeled 1 through 6:

1. **Rolling a number greater than 1**: The possible outcomes are 2, 3, 4, 5, and 6. This gives us 5 favorable outcomes out of 6 total outcomes. The probability is \( \frac{5}{6} \).

2. **Rolling a number less than or equal to 6**: All outcomes (1, 2, 3, 4, 5, and 6) meet this condition. This gives us 6 favorable outcomes out of 6 total outcomes. The probability is \( 1 \) (or 100%).

3. **Rolling a 6**: There is only 1 favorable outcome (rolling a 6) out of 6 total outcomes. The probability is \( \frac{1}{6} \).

4. **Rolling an odd number**: The odd numbers on the die are 1, 3, and 5. This gives us 3 favorable outcomes out of 6 total outcomes. The probability is \( \frac{1}{2} \).

5. **Rolling a zero**: A standard number cube does not have a zero on any face, so there are 0 favorable outcomes out of 6 total outcomes. The probability is \( 0 \).

Now, you can place these probabilities on a probability scale from 0 to 1:

- \( 0 \): Rolling a zero
- \( \frac{1}{6} \): Rolling a 6
- \( \frac{1}{2} \): Rolling an odd number
- \( \frac{5}{6} \): Rolling a number greater than 1
- \( 1 \): Rolling a number less than or equal to 6

You would drag each event to the appropriate point on the scale according to their probabilities.