To find the frequencies corresponding to the wavelengths given (2.75 to 16.5 meters), we can use the formula that relates the speed of sound (v), frequency (f), and wavelength (λ):
\[ v = f \times \lambda \]
Rearranging this gives us:
\[ f = \frac{v}{\lambda} \]
Given the speed of sound \( v \approx 330 , \text{m/s} \), we can calculate the frequencies for the two wavelengths:
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For the minimum wavelength (λ = 2.75 m): \[ f = \frac{330 , \text{m/s}}{2.75 , \text{m}} \approx 120 , \text{Hz} \]
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For the maximum wavelength (λ = 16.5 m): \[ f = \frac{330 , \text{m/s}}{16.5 , \text{m}} \approx 20 , \text{Hz} \]
Thus, the frequencies that correspond to these wavelengths range from approximately 20 Hz to 120 Hz.
So, the correct response is: 20 to 120 hertz.