Question

If you toss two coins simultaneously, what is the probability of getting exactly one head? Write your answer in the simplest form of fraction.(1 point)
Responses

28
Start Fraction 2 over 8 End Fraction

14
Start Fraction 1 over 4 End Fraction

18
Start Fraction 1 over 8 End Fraction

12

Answer 1

When tossing two coins, there are four possible outcomes:

1. Heads (H), Heads (H)
2. Heads (H), Tails (T)
3. Tails (T), Heads (H)
4. Tails (T), Tails (T)

Of these outcomes, the ones that result in exactly one head are:

- Heads (H), Tails (T)
- Tails (T), Heads (H)

So, there are 2 outcomes that give exactly one head out of a total of 4 outcomes.

The probability of getting exactly one head is therefore:

\[
P(\text{exactly one head}) = \frac{\text{Number of favorable outcomes}}{\text{Total outcomes}} = \frac{2}{4} = \frac{1}{2}
\]

However, from the options you've provided, it looks like I need to provide it in the simplest form as listed:

The answer in the options given does not match exactly since "1/2" is not listed. The options appear to be fractions that need to be interpreted correctly.

The correct simplified probability is \(\frac{1}{2}\), and the closest interpretation or option from your list might be \( \frac{2}{4} \).

Yet, \(\frac{1}{2}\) is indeed the accurate fraction.

Please check the options as there might be an error in the presentation or transcription!