Question
Jared has a bag filled with coins. He randomly takes out a coin, records its type, and places it back into the bag. He performs this 40 times. The table shows the results he recorded.
Type of Coin Number of Times Picked
Nickel
Dime
Quarter
Penny
Select the correct probability model that represents this situation.
A.
S = {nickel, dime, quarter, penny}
P(nickel) = , P(dime) = , P(quarter) = , P(penny) =
B.
S = {nickel, dime, quarter, penny}
P(nickel) = , P(dime) = , P(quarter) = , P(penny) =
C.
S = {nickel, dime, quarter, penny}
P(nickel) = , P(dime) = , P(quarter) = , P(penny) =
D.
S = {nickel, dime, quarter, penny}
P(nickel) = , P(dime) = , P(quarter) = , P(penny) =
Type of Coin Number of Times Picked
Nickel
Dime
Quarter
Penny
Select the correct probability model that represents this situation.
A.
S = {nickel, dime, quarter, penny}
P(nickel) = , P(dime) = , P(quarter) = , P(penny) =
B.
S = {nickel, dime, quarter, penny}
P(nickel) = , P(dime) = , P(quarter) = , P(penny) =
C.
S = {nickel, dime, quarter, penny}
P(nickel) = , P(dime) = , P(quarter) = , P(penny) =
D.
S = {nickel, dime, quarter, penny}
P(nickel) = , P(dime) = , P(quarter) = , P(penny) =
Answers
GPT-4o mini
In order to select the correct probability model that represents the situation described, we need to calculate the probabilities of Jared picking each type of coin based on the results he recorded.
First, let's assume Jared has recorded the counts of how many times each type of coin was picked in the 40 trials.
For example, if he recorded:
- Nickel: 10 times
- Dime: 12 times
- Quarter: 8 times
- Penny: 10 times
We would calculate the probabilities by taking the number of times each coin was picked and dividing it by the total number of picks (which is 40).
So, the probabilities would be:
- \( P(nickel) = \frac{10}{40} = 0.25 \)
- \( P(dime) = \frac{12}{40} = 0.30 \)
- \( P(quarter) = \frac{8}{40} = 0.20 \)
- \( P(penny) = \frac{10}{40} = 0.25 \)
Thus, we would summarize this in the form of a probability model:
A.
S = {nickel, dime, quarter, penny}
P(nickel) = 0.25, P(dime) = 0.30, P(quarter) = 0.20, P(penny) = 0.25
If the options A, B, C, and D provided don't include actual numbers but are open fields, it is likely you fill in each option with your calculated values. Since the example above corresponds with A, based on the values you have you fill in the correct probabilities in the blank spaces.
In conclusion, if your recorded values fit the provided expressions, choose the one accordingly. However, without specific numbers provided in the options, it’s not possible to directly select one among A, B, C, or D. You'll need to match the calculated probabilities based on your data to the closest format provided.
First, let's assume Jared has recorded the counts of how many times each type of coin was picked in the 40 trials.
For example, if he recorded:
- Nickel: 10 times
- Dime: 12 times
- Quarter: 8 times
- Penny: 10 times
We would calculate the probabilities by taking the number of times each coin was picked and dividing it by the total number of picks (which is 40).
So, the probabilities would be:
- \( P(nickel) = \frac{10}{40} = 0.25 \)
- \( P(dime) = \frac{12}{40} = 0.30 \)
- \( P(quarter) = \frac{8}{40} = 0.20 \)
- \( P(penny) = \frac{10}{40} = 0.25 \)
Thus, we would summarize this in the form of a probability model:
A.
S = {nickel, dime, quarter, penny}
P(nickel) = 0.25, P(dime) = 0.30, P(quarter) = 0.20, P(penny) = 0.25
If the options A, B, C, and D provided don't include actual numbers but are open fields, it is likely you fill in each option with your calculated values. Since the example above corresponds with A, based on the values you have you fill in the correct probabilities in the blank spaces.
In conclusion, if your recorded values fit the provided expressions, choose the one accordingly. However, without specific numbers provided in the options, it’s not possible to directly select one among A, B, C, or D. You'll need to match the calculated probabilities based on your data to the closest format provided.