Question

Jeremy has a vase that contains red, blue, and green marbles. He draws a marble from the vase, records the result in the chart below, and replaces the marble. Jeremy repeats these steps 20 times.

Draw Outcomes
blue green blue blue
green blue blue blue
blue green blue green
blue blue green blue
blue red blue blue


Using the data in the chart, determine the experimental probability of each color.
A.
P(blue) = 0.7
P(green) = 0.25
P(red) = 0.05

B.
P(blue) = 0.75
P(green) = 0.20
P(red) = 0.05

C.
P(blue) = 0.7
P(green) = 0.25
P(red) = 0.5

D.
P(blue) = 0.5
P(green) = 0.25
P(red) = 0.25

Answer 1

To find the experimental probability of each color marble, we first need to count the total number of marbles drawn for each color from the chart.

**Analysis of Draw Outcomes:**
From the chart provided, the draw outcomes are:

```
blue
green
blue
blue
green
blue
blue
blue
blue
green
blue
green
blue
blue
green
blue
blue
red
blue
blue
```

Let's count the occurrences of each color:

- **Blue:** There are 15 occurrences of blue.
- **Green:** There are 5 occurrences of green.
- **Red:** There is 1 occurrence of red.

**Calculating Total Draws:**
The total number of draws is 20.

**Calculating Probabilities:**

1. **P(blue):**
\[
P(blue) = \frac{\text{Number of blue draws}}{\text{Total draws}} = \frac{15}{20} = 0.75
\]

2. **P(green):**
\[
P(green) = \frac{\text{Number of green draws}}{\text{Total draws}} = \frac{5}{20} = 0.25
\]

3. **P(red):**
\[
P(red) = \frac{\text{Number of red draws}}{\text{Total draws}} = \frac{1}{20} = 0.05
\]

**Final Results:**
- \( P(blue) = 0.75 \)
- \( P(green) = 0.25 \)
- \( P(red) = 0.05 \)

Based on these calculations, the correct answer is:

**B.**
P(blue) = 0.75
P(green) = 0.20
P(red) = 0.05