Question

4.09 Collaborative Activity Physics IB
Question 1
A series circuit with three resistors.

Mark the things you know directly from this diagram.

Voltage

V

Current

I

Power

P

Resistance

R

Load 1 / R1




Load 2 / R2




Load 3 / R3




Source / Total




Question 2
Series circuit with three resistors.
V I P R
Load 1 / R1
Choose...

Choose...

Choose...

Choose...

Question 3
Series circuit with three resistors.
The current in the first resistor is
A.
Question 4
Series circuit with three resistors.
The power dissipated in resistor 1 is
W
Question 5
Series circuit with three resistors.

Use the information from the diagram and the previous answer to give what you know about the total/source parameters.


V

I

P

R

Total/ Source
Choose...

Choose...

Choose...

Choose...
Question 6
Series circuit with three resistors.



The total resistance of the circuit is
Ω.
Question 7
Series circuit with three resistors.
The total power delivered by the source is
W.

Answer 1

To help you with the series circuit with three resistors, let's break down each question based on the standard rules of a series circuit.

### Question 1
In a series circuit, we can directly state the following relationships:

- **Voltage (V)**: Total voltage is the sum of the voltages across each resistor.
- **Current (I)**: The current is the same through all components in a series circuit.
- **Power (P)**: The power dissipated in each resistor can be calculated using \( P = I^2 R \).
- **Resistance (R)**: The total resistance is the sum of individual resistances: \( R_{total} = R_1 + R_2 + R_3 \).

#### Load Parameters
- Load 1 / R1: \( R_1 \)
- Load 2 / R2: \( R_2 \)
- Load 3 / R3: \( R_3 \)
- Source / Total:
- Voltage \( V_{total} = V_1 + V_2 + V_3 \)
- Current \( I_{total} = I_1 = I_2 = I_3 \)
- Power \( P_{total} = P_1 + P_2 + P_3 \)
- Resistance \( R_{total} = R_1 + R_2 + R_3 \)

### Question 2
For this question, you would fill in values relevant to your circuit, but as a general template:

- Load 1 / R1:
- V: (Voltage across R1)
- I: (Current through R1)
- P: \( I^2 R_1 \)
- R: \( R_1 \)

- Load 2 / R2:
- V:
- I:
- P: \( I^2 R_2 \)
- R: \( R_2 \)

- Load 3 / R3:
- V:
- I:
- P: \( I^2 R_3 \)
- R: \( R_3 \)

### Question 3
Since the current is the same in all resistors in a series circuit, you would write the current (I) which is constant and equal to the total current (I_total).

### Question 4
To calculate the power dissipated in resistor 1 (R1):

\[ P_1 = I^2 R_1 \]

### Question 5
Again, using the previous information and calculations:

- **Total Voltage (V_total)**: (Sum of the voltages across all resistors)
- **Total Current (I_total)**: (Same as the current through each resistor)
- **Total Power (P_total)**: \( P_1 + P_2 + P_3 \)
- **Total Resistance (R_total)**: \( R_1 + R_2 + R_3 \)

### Question 6
The total resistance \( R_{total} \) is calculated as:

\[ R_{total} = R_1 + R_2 + R_3 \]

### Question 7
The total power delivered by the source can be calculated as follows:

\[ P_{total} = V_{total} \times I_{total} \]

Where \( V_{total} \) is the total voltage supplied to the circuit.

### Summary
To complete your answers, you need to input specific values for voltage, current, and resistance based on your specific circuit diagram. If you have those values or if you need help with calculations, feel free to provide them!