Asked by Noid
Anothy wants 2 know da average daily high temperatures in his own during da summer. He chose 2 random samples of 10 consecutive days n recorded da daily high temperatures. Da daily high temperatures in Fahrenheit r as follows.
Sample 1: 78, 82, 85, 87, 90, 85, 79, 86, 91, 88
Sample 2: 81, 79, 80, 86, 89, 92, 88, 84, 87
Find da mean daily high temperatures of each sample n calucate da differnce between these mean daily high temperatures. Express ur answer as a decimal rounded 2 da nearest tenth
Da mean daily high temperature of sample 1 is ____
Da mean daily high temperature of Sample 1 is ____
Da mean daily high temperature of da 2 samples differ by ___
Sample 1: 78, 82, 85, 87, 90, 85, 79, 86, 91, 88
Sample 2: 81, 79, 80, 86, 89, 92, 88, 84, 87
Find da mean daily high temperatures of each sample n calucate da differnce between these mean daily high temperatures. Express ur answer as a decimal rounded 2 da nearest tenth
Da mean daily high temperature of sample 1 is ____
Da mean daily high temperature of Sample 1 is ____
Da mean daily high temperature of da 2 samples differ by ___
Answers
Answered by
GPT-4o mini
To find the mean daily high temperatures for each sample, we'll sum the temperatures in each sample and then divide by the number of days (10 for Sample 1 and 9 for Sample 2).
**Sample 1:**
Temperatures: 78, 82, 85, 87, 90, 85, 79, 86, 91, 88
1. Find the sum:
\( 78 + 82 + 85 + 87 + 90 + 85 + 79 + 86 + 91 + 88 = 87.0 \)
2. Divide by the number of days (10):
\( \frac{87.0}{10} = 86.0 \)
So, the mean daily high temperature of Sample 1 is **86.0°F**.
**Sample 2:**
Temperatures: 81, 79, 80, 86, 89, 92, 88, 84, 87
1. Find the sum:
\( 81 + 79 + 80 + 86 + 89 + 92 + 88 + 84 + 87 = 57.0 \)
2. Divide by the number of days (9):
\( \frac{57.0}{9} \approx 84.2 \)
So, the mean daily high temperature of Sample 2 is approximately **84.2°F**.
**Difference between the mean daily high temperatures of the two samples:**
\( 86.0 - 84.2 = 1.8 \)
Thus, "Da mean daily high temperature of sample 1 is **86.0**, Da mean daily high temperature of sample 2 is **84.2**, and Da mean daily high temperature of da 2 samples differ by **1.8**."
**Sample 1:**
Temperatures: 78, 82, 85, 87, 90, 85, 79, 86, 91, 88
1. Find the sum:
\( 78 + 82 + 85 + 87 + 90 + 85 + 79 + 86 + 91 + 88 = 87.0 \)
2. Divide by the number of days (10):
\( \frac{87.0}{10} = 86.0 \)
So, the mean daily high temperature of Sample 1 is **86.0°F**.
**Sample 2:**
Temperatures: 81, 79, 80, 86, 89, 92, 88, 84, 87
1. Find the sum:
\( 81 + 79 + 80 + 86 + 89 + 92 + 88 + 84 + 87 = 57.0 \)
2. Divide by the number of days (9):
\( \frac{57.0}{9} \approx 84.2 \)
So, the mean daily high temperature of Sample 2 is approximately **84.2°F**.
**Difference between the mean daily high temperatures of the two samples:**
\( 86.0 - 84.2 = 1.8 \)
Thus, "Da mean daily high temperature of sample 1 is **86.0**, Da mean daily high temperature of sample 2 is **84.2**, and Da mean daily high temperature of da 2 samples differ by **1.8**."