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What is the probability of an offspring that has a homozygous dominant genotype for pea seed color as shown in the Punnett square? (1 point)

Responses

0%

25%

50%

100%

1 answer

To determine the probability of an offspring having a homozygous dominant genotype for pea seed color, we need to examine the Punnett square that represents the cross of the parental genotypes.

Let's assume that "Y" represents the dominant allele for yellow seed color and "y" represents the recessive allele for green seed color. A homozygous dominant genotype would be represented as "YY."

If we consider a cross between two heterozygous plants (Yy x Yy), the Punnett square would look like this:

       Y    |    y
    -----------------
Y |   YY   |   Yy
    -----------------
y |   Yy   |   yy

From the Punnett square, the genotypes of the offspring are:

  • 1 YY (homozygous dominant)
  • 2 Yy (heterozygous)
  • 1 yy (homozygous recessive)

This gives us a total of 4 possible genotypes:

  • 1 YY (25%)
  • 2 Yy (50%)
  • 1 yy (25%)

Thus, the probability of an offspring having a homozygous dominant genotype (YY) is 25%.

So, the answer is: 25%