To determine the correctness of the statements, let's calculate the mean, median, and range for each company.
Company A Ages
Ages: 34, 28, 36, 27, 45, 44, 30, 42, 41, 40, 50, 48, 52, 45, 39, 38
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Mean: \[ \text{Mean} = \frac{\text{Sum of ages}}{\text{Number of employees}} = \frac{34 + 28 + 36 + 27 + 45 + 44 + 30 + 42 + 41 + 40 + 50 + 48 + 52 + 45 + 39 + 38}{16} \] \[ = \frac{ 454 }{ 16 } \approx 28.375 \]
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Median: First, sort the ages in ascending order: 27, 28, 30, 34, 36, 38, 39, 40, 41, 42, 44, 45, 45, 48, 50, 52
Since there are 16 data points, the median is the average of the 8th and 9th values: \[ \text{Median} = \frac{ 40 + 41 }{ 2 } = 40.5 \]
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Range: \[ \text{Range} = \text{Max} - \text{Min} = 52 - 27 = 25 \]
Company B Ages
Ages: 29, 32, 48, 51, 49, 37, 33, 35, 36, 40, 45, 48, 43, 43, 44, 48
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Mean: \[ \text{Mean} = \frac{29 + 32 + 48 + 51 + 49 + 37 + 33 + 35 + 36 + 40 + 45 + 48 + 43 + 43 + 44 + 48}{16} = \frac{ 723 }{ 16 } \approx 45.1875 \]
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Median: First, sort the ages in ascending order: 29, 32, 33, 35, 36, 37, 40, 43, 43, 44, 45, 48, 48, 48, 49, 51
The median is the average of the 8th and 9th values: \[ \text{Median} = \frac{43 + 43}{2} = 43 \]
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Range: \[ \text{Range} = \text{Max} - \text{Min} = 51 - 29 = 22 \]
Comparison of Means, Medians, and Ranges
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Mean: \[ \text{Mean (A)} \approx 40.25 \quad \text{and} \quad \text{Mean (B)} \approx 45.1875 \] Company A's mean is lower than Company B's.
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Median: \[ \text{Median (A)} = 40.5 \quad \text{and} \quad \text{Median (B)} = 43 \] Company A's median is lower than Company B's.
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Range: \[ \text{Range (A)} = 25 \quad \text{and} \quad \text{Range (B)} = 22 \] Company A's range is higher than Company B's.
Conclusion
- Statement 1: False (mean A < mean B)
- Statement 2: True (median A < median B)
- Statement 3: True (range A > range B)
The correct option is:
- statements 2 and 3.