Asked by Noelle
What volume of 0.105 M HNO3, in milliliters, is required to react completely with 1.40 g of Ba(OH)2?
2 HNO3(aq) + Ba(OH)2(s) Ba(NO3)2(aq) + 2 H2O(l)
2 HNO3(aq) + Ba(OH)2(s) Ba(NO3)2(aq) + 2 H2O(l)
Answers
Answered by
DrBob222
Convert 1.4 g Ba(OH)2 to moles. moles = grams/molar mass
Using the coefficients in the balanced equation, convert moles Ba(OH)2 to moles HNO3.
Finally, M = moles/L soln. You have M HNO3 and moles HNO3, solve for L.
Using the coefficients in the balanced equation, convert moles Ba(OH)2 to moles HNO3.
Finally, M = moles/L soln. You have M HNO3 and moles HNO3, solve for L.
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