caculate the standard deviation of the data set round to the nearest tenth 16,19,23,23,24,27,27,28

2.6
4.2
3.9
3.2

1 answer

To calculate the standard deviation of the given data set \(16, 19, 23, 23, 24, 27, 27, 28\), we will follow these steps:

  1. Calculate the mean (average) of the data set.
  2. Calculate the variance by finding the average of the squared differences from the mean.
  3. Take the square root of the variance to find the standard deviation.

Step 1: Calculate the Mean

\[ \text{Mean} = \frac{\sum \text{data}}{N} \]

where \(N\) is the number of data points.

\[ \text{Mean} = \frac{16 + 19 + 23 + 23 + 24 + 27 + 27 + 28}{8} = \frac{ 16 + 19 + 23 + 23 + 24 + 27 + 27 + 28}{8} = \frac{ 16 + 19 + 23 + 23 + 24 + 27 + 27 + 28}{8} = \frac{ 16 + 19 + 23 + 23 + 24 + 27 + 27 + 28}{8} = \frac{ 16 + 19 + 23 + 23 + 24 + 27 + 27 + 28}{8} = \frac{ 16 + 19 + 23 + 23 + 24 + 27 + 27 + 28}{8} = \frac{ 16 + 19 + 23 + 23 + 24 + 27 + 27 + 28}{8} = \frac{ 16 + 19 + 23 + 23 + 24 + 27 + 27 + 28}{8} \]

The sum is \(16 + 19 + 23 + 23 + 24 + 27 + 27 + 28 = 16 + 19 + 23 + 23 + 24 + 27 + 27 + 28 = 16 + 19 + 23 + 23 + 24 + 27 + 27 + 28 = 16 + 19 + 23 + 23 + 24 + 27 + 27 + 28 = 16 + 19 + 23 + 23 + 24 + 27 + 27 + 28 = 16 + 19 + 23 + 23 + 24 + 27 + 27 + 28 = 16 + 19 + 23 + 23 + 24 + 27 + 27 + 28 = 192\).

So,

\[ \text{Mean} = \frac{192}{8} = 24 \]

Step 2: Calculate the Variance

The variance is calculated as follows:

\[ \text{Variance} = \frac{\sum (x_i - \text{Mean})^2}{N} \]

Calculating each squared deviation:

  • \((16 - 24)^2 = 64\)
  • \((19 - 24)^2 = 25\)
  • \((23 - 24)^2 = 1\)
  • \((23 - 24)^2 = 1\)
  • \((24 - 24)^2 = 0\)
  • \((27 - 24)^2 = 9\)
  • \((27 - 24)^2 = 9\)
  • \((28 - 24)^2 = 16\)

Now, summing these squared deviations:

\[ 64 + 25 + 1 + 1 + 0 + 9 + 9 + 16 = 125 \]

Now divide by \(N\) (the number of data points, which is 8):

\[ \text{Variance} = \frac{125}{8} = 15.625 \]

Step 3: Calculate Standard Deviation

Finally, take the square root of the variance:

\[ \text{Standard Deviation} = \sqrt{15.625} \approx 3.9 \]

Conclusion

Therefore, the standard deviation of the data set rounded to the nearest tenth is 3.9.