Question

Bryant rolls a die and then flips a coin. What is the probability he will get a 3 and then a heads? Round your answer to 4 places.



Group of answer choices

.0833

.6667

.5

.1667

Answer 1

To find the probability that Bryant rolls a 3 on a die and then flips a heads on a coin, we need to calculate the probability of each event and then multiply them together.

1. **Probability of rolling a 3 on a die:**
A standard die has 6 faces, with numbers 1 through 6. The probability of rolling a 3 is:
\[
P(3) = \frac{1}{6}
\]

2. **Probability of flipping heads on a coin:**
A standard coin has 2 sides: heads and tails. The probability of flipping heads is:
\[
P(\text{heads}) = \frac{1}{2}
\]

3. **Calculating the combined probability:**
The two events (rolling the die and flipping the coin) are independent, so we can multiply their probabilities together:
\[
P(3 \text{ and heads}) = P(3) \times P(\text{heads}) = \frac{1}{6} \times \frac{1}{2} = \frac{1}{12}
\]

4. **Converting to decimal:**
\[
\frac{1}{12} \approx 0.0833
\]

Therefore, rounding to four decimal places, the probability that Bryant will get a 3 and then a heads is:
\[
\text{Probability} \approx 0.0833
\]

The correct answer is **0.0833**.