A team of students builds a lever as a science project. They expend 10,300 Joules of energy to lift some bricks with the lever. If 6,283 Joules of energy are applied to the bricks, what is the lever’s efficiency?(1 point) Responses 0.61% 0.61% 164% 164% 39% 39% 61%

Answer 1

To calculate the efficiency of the lever, you can use the formula:

\[ \text{Efficiency} = \left( \frac{\text{Useful energy output}}{\text{Total energy input}} \right) \times 100 \]

In this case:

• Useful energy output = 6,283 Joules (energy applied to the bricks)
• Total energy input = 10,300 Joules (energy expended)

Now, plug the values into the formula:

\[ \text{Efficiency} = \left( \frac{6283 \text{ J}}{10300 \text{ J}} \right) \times 100 \]

Calculating this gives:

\[ \text{Efficiency} = \left( 0.609 \right) \times 100 \approx 60.9% \]

Rounding this to the nearest whole number gives approximately 61%.

So, the lever’s efficiency is 61%.