To complete the table using the equation \( f(x) = 350(1.22)^x \), we'll calculate the values for \( f(x) \) for \( x = 0, 1, 2, 3, 4, 5 \).
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For \( x = 0 \): \[ f(0) = 350(1.22)^0 = 350(1) = 350 \]
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For \( x = 1 \): \[ f(1) = 350(1.22)^1 = 350(1.22) \approx 427.0 \]
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For \( x = 2 \): \[ f(2) = 350(1.22)^2 = 350(1.4884) \approx 520.9 \]
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For \( x = 3 \): \[ f(3) = 350(1.22)^3 = 350(1.8049) \approx 631.7 \]
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For \( x = 4 \): \[ f(4) = 350(1.22)^4 = 350(2.1997) \approx 769.9 \]
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For \( x = 5 \): \[ f(5) = 350(1.22)^5 = 350(2.6756) \approx 936.5 \]
Now we can summarize the values in a table:
| \( x \) | \( f(x) \) | |:---------:|:-------------:| | 0 | 350.0 | | 1 | 427.0 | | 2 | 520.9 | | 3 | 631.7 | | 4 | 769.9 | | 5 | 936.5 |
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