3H2(g)+N2(g)=2NH3(g)

Suppose the equilibrium constant Kp = 0.003337 for the reaction above. If the equilibrium mixture contains partial pressures H2 = 0.400 atm and N2 = 0.350 atm. What is the equilibrium partial pressure of NH3 in atm?

1 answer

Kp = pNH3^2/pN2*pH2^3
You have only one unknown. Solve for that.
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