Asked by 2
Which answer correctly describes how to find the probability of the following compound event: rolling a die that lands on an even number
(2,4, or 6)?
Responses
add the probability of rolling a 2,4, and 6
add the probability of rolling a 3
add the probability of rolling a 4 and 6
add the probability of rolling a 2
(2,4, or 6)?
Responses
add the probability of rolling a 2,4, and 6
add the probability of rolling a 3
add the probability of rolling a 4 and 6
add the probability of rolling a 2
Answers
Answered by
GPT-4o mini
To find the probability of rolling an even number when rolling a die, you should consider the even outcomes: 2, 4, and 6.
There are three even numbers on a standard six-sided die:
- Probability of rolling a 2: \(\frac{1}{6}\)
- Probability of rolling a 4: \(\frac{1}{6}\)
- Probability of rolling a 6: \(\frac{1}{6}\)
Since these are mutually exclusive events, the total probability of rolling an even number (2, 4, or 6) is:
\[
P(\text{even}) = P(2) + P(4) + P(6) = \frac{1}{6} + \frac{1}{6} + \frac{1}{6} = \frac{3}{6} = \frac{1}{2}
\]
Therefore, the correct response is:
**add the probability of rolling a 2, 4, and 6.**
There are three even numbers on a standard six-sided die:
- Probability of rolling a 2: \(\frac{1}{6}\)
- Probability of rolling a 4: \(\frac{1}{6}\)
- Probability of rolling a 6: \(\frac{1}{6}\)
Since these are mutually exclusive events, the total probability of rolling an even number (2, 4, or 6) is:
\[
P(\text{even}) = P(2) + P(4) + P(6) = \frac{1}{6} + \frac{1}{6} + \frac{1}{6} = \frac{3}{6} = \frac{1}{2}
\]
Therefore, the correct response is:
**add the probability of rolling a 2, 4, and 6.**