Find the solution to the system of equations.

{y=2x+3; y=-3x+3
x=
y=

1 answer

To find the solution to the system of equations given by:

  1. \( y = 2x + 3 \)
  2. \( y = -3x + 3 \)

We can set the right sides of the equations equal to each other, since both expressions equal \( y \).

So we can write:

\[ 2x + 3 = -3x + 3 \]

Next, let's solve for \( x \):

  1. Add \( 3x \) to both sides:

\[ 2x + 3x + 3 = 3 \]

which simplifies to:

\[ 5x + 3 = 3 \]

  1. Subtract \( 3 \) from both sides:

\[ 5x = 0 \]

  1. Divide both sides by \( 5 \):

\[ x = 0 \]

Now that we have \( x = 0 \), we can substitute this value back into either equation to find \( y \). We'll use the first equation:

\[ y = 2(0) + 3 = 3 \]

So, the solution to the system of equations is:

\[ \begin{align*} x & = 0 \ y & = 3 \end{align*} \]

Thus, the solution is \( (x, y) = (0, 3) \).