Question
Mr. Kennedy raised beef cattle. The stock tank near the windmill has a diameter of 3 meters. When it is full, the water is 1.5 meters deep. How many cubic meters of water are in the stock tank when it is full? Use 3.14 for pi.
7.1
14.1
42.4
10.6
7.1
14.1
42.4
10.6
Answers
GPT-4o mini
To find the volume of water in the stock tank when it is full, we can use the formula for the volume of a cylinder, which is:
\[
V = \pi r^2 h
\]
Where:
- \( V \) is the volume,
- \( \pi \) is approximately 3.14,
- \( r \) is the radius of the cylinder, and
- \( h \) is the height (or depth) of the water.
Given:
- The diameter of the stock tank is 3 meters, so the radius \( r \) is half of that:
\[
r = \frac{3}{2} = 1.5 \text{ meters}
\]
- The height \( h \) is given as 1.5 meters.
Now, we can plug in the values:
\[
V = 3.14 \times (1.5)^2 \times 1.5
\]
Calculating \( (1.5)^2 \):
\[
(1.5)^2 = 2.25
\]
Now substituting this value back into the volume formula:
\[
V = 3.14 \times 2.25 \times 1.5
\]
Now we calculate \( 2.25 \times 1.5 \):
\[
2.25 \times 1.5 = 3.375
\]
Now, substituting this value back into the volume formula:
\[
V = 3.14 \times 3.375
\]
Calculating that gives:
\[
V \approx 10.6075
\]
Rounding this to one decimal place, we get approximately 10.6 cubic meters.
So the volume of water in the stock tank when it is full is:
\[
\boxed{10.6}
\]
\[
V = \pi r^2 h
\]
Where:
- \( V \) is the volume,
- \( \pi \) is approximately 3.14,
- \( r \) is the radius of the cylinder, and
- \( h \) is the height (or depth) of the water.
Given:
- The diameter of the stock tank is 3 meters, so the radius \( r \) is half of that:
\[
r = \frac{3}{2} = 1.5 \text{ meters}
\]
- The height \( h \) is given as 1.5 meters.
Now, we can plug in the values:
\[
V = 3.14 \times (1.5)^2 \times 1.5
\]
Calculating \( (1.5)^2 \):
\[
(1.5)^2 = 2.25
\]
Now substituting this value back into the volume formula:
\[
V = 3.14 \times 2.25 \times 1.5
\]
Now we calculate \( 2.25 \times 1.5 \):
\[
2.25 \times 1.5 = 3.375
\]
Now, substituting this value back into the volume formula:
\[
V = 3.14 \times 3.375
\]
Calculating that gives:
\[
V \approx 10.6075
\]
Rounding this to one decimal place, we get approximately 10.6 cubic meters.
So the volume of water in the stock tank when it is full is:
\[
\boxed{10.6}
\]