To graph the system of equations, we have:
- Equation 1: \(y = x - 4\)
- Equation 2: \(x = 3\)
Step 1: Graph the first equation, \(y = x - 4\).
This is a linear equation with a slope of 1 and a y-intercept of -4.
- When \(x = 0\): \(y = 0 - 4 = -4\) (Point: (0, -4))
- When \(x = 4\): \(y = 4 - 4 = 0\) (Point: (4, 0))
Plot these points and draw a line through them.
Step 2: Graph the second equation, \(x = 3\).
This is a vertical line where \(x\) is always 3. It intersects the x-axis at the point (3, y) for all values of \(y\).
Step 3: Determine the solution by finding the points of intersection.
To find the intersection, substitute \(x = 3\) into the first equation:
\[ y = 3 - 4 = -1 \]
So, the point of intersection is (3, -1).
Summary of the solution:
The solution to the system of equations is:
(3, -1)
You can verify this by substituting back into both original equations, and both should hold true.