To determine if (1, 1) is a solution to the system of equations, we will substitute \( x = 1 \) and \( y = 1 \) into both equations.
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For the first equation \( 6x + 14y = 20 \): \[ 6(1) + 14(1) = 6 + 14 = 20 \] Since both sides are equal, (1, 1) is a solution to the first equation.
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For the second equation \( 8x + y = 6 \): \[ 8(1) + 1 = 8 + 1 = 9 \] Since \( 9 \neq 6 \), (1, 1) is not a solution to the second equation.
Since (1, 1) satisfies the first equation but not the second, it is not a solution to the system of equations.