Question
What is the length of segment AC?
On a coordinate plane, line A C has points (3, negative 1) and (negative 5, 5).
On a coordinate plane, line A C has points (3, negative 1) and (negative 5, 5).
Answers
Answered by
GPT-4o mini
To find the length of segment AC between the points \( A(3, -1) \) and \( C(-5, 5) \), we can use the distance formula:
\[
d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}
\]
In this case, we have:
- \( (x_1, y_1) = (3, -1) \)
- \( (x_2, y_2) = (-5, 5) \)
Now, we can plug the coordinates into the formula:
\[
d = \sqrt{((-5) - 3)^2 + (5 - (-1))^2}
\]
Now, calculate the differences:
\[
x_2 - x_1 = -5 - 3 = -8
\]
\[
y_2 - y_1 = 5 - (-1) = 5 + 1 = 6
\]
Now, substitute these differences back into the distance formula:
\[
d = \sqrt{(-8)^2 + (6)^2}
\]
Calculating the squares:
\[
(-8)^2 = 64
\]
\[
(6)^2 = 36
\]
Now, add these values:
\[
d = \sqrt{64 + 36}
\]
\[
d = \sqrt{100}
\]
\[
d = 10
\]
Thus, the length of segment AC is \( \boxed{10} \).
\[
d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}
\]
In this case, we have:
- \( (x_1, y_1) = (3, -1) \)
- \( (x_2, y_2) = (-5, 5) \)
Now, we can plug the coordinates into the formula:
\[
d = \sqrt{((-5) - 3)^2 + (5 - (-1))^2}
\]
Now, calculate the differences:
\[
x_2 - x_1 = -5 - 3 = -8
\]
\[
y_2 - y_1 = 5 - (-1) = 5 + 1 = 6
\]
Now, substitute these differences back into the distance formula:
\[
d = \sqrt{(-8)^2 + (6)^2}
\]
Calculating the squares:
\[
(-8)^2 = 64
\]
\[
(6)^2 = 36
\]
Now, add these values:
\[
d = \sqrt{64 + 36}
\]
\[
d = \sqrt{100}
\]
\[
d = 10
\]
Thus, the length of segment AC is \( \boxed{10} \).