Question
A) Which student is using innovative problem-solving to investigate potential energy and kinetic
energy? (1 point)
Meghan replicates a demonstration of potential energy and kinetic energy she found in her science
textbook.
Lisa thinks about ways that potential energy and kinetic energy occur in her own life, chooses one,
and designs a demonstration to show the relationship between the two kinds of energy.
Pedro researches potential and kinetic energy at the library and writes a report on the relationship
between them.
William searches the internet for experiments involving potential and kinetic energy, chooses one,
and carries it out.
A)
How much more kinetic energy does a 6-kilogram bowling ball have when it is rolling at 16 mph
(7.1 meters per second) than when it is rolling at 14 mph (6.2 meters per second)?
KE =
1
2
mv
2
(1 point)
35.9 J
266.5 J
1.3 J
151.2 J
energy? (1 point)
Meghan replicates a demonstration of potential energy and kinetic energy she found in her science
textbook.
Lisa thinks about ways that potential energy and kinetic energy occur in her own life, chooses one,
and designs a demonstration to show the relationship between the two kinds of energy.
Pedro researches potential and kinetic energy at the library and writes a report on the relationship
between them.
William searches the internet for experiments involving potential and kinetic energy, chooses one,
and carries it out.
A)
How much more kinetic energy does a 6-kilogram bowling ball have when it is rolling at 16 mph
(7.1 meters per second) than when it is rolling at 14 mph (6.2 meters per second)?
KE =
1
2
mv
2
(1 point)
35.9 J
266.5 J
1.3 J
151.2 J
Answers
Answered by
GPT-4o mini
A) The student who is using innovative problem-solving to investigate potential energy and kinetic energy is **Lisa**. She is thinking about ways that potential energy and kinetic energy occur in her own life, choosing one, and designing a demonstration to show the relationship between the two kinds of energy.
B) To calculate the change in kinetic energy (KE) of the bowling ball, we can use the formula for kinetic energy:
\[
KE = \frac{1}{2} mv^2
\]
where:
- \( m \) is the mass (6 kg for the bowling ball),
- \( v \) is the velocity (converted to meters per second).
1. **Calculate KE at 16 mph (7.1 m/s)**:
\[
KE_{16} = \frac{1}{2} \times 6 \, \text{kg} \times (7.1 \, \text{m/s})^2
\]
\[
KE_{16} = 3 \times 50.41 = 151.23 \, \text{J}
\]
2. **Calculate KE at 14 mph (6.2 m/s)**:
\[
KE_{14} = \frac{1}{2} \times 6 \, \text{kg} \times (6.2 \, \text{m/s})^2
\]
\[
KE_{14} = 3 \times 38.44 = 115.32 \, \text{J}
\]
3. **Find the difference in kinetic energy**:
\[
\Delta KE = KE_{16} - KE_{14}
\]
\[
\Delta KE = 151.23 \, \text{J} - 115.32 \, \text{J} = 35.91 \, \text{J}
\]
The answer rounded to one decimal place is approximately **35.9 J**.
Therefore, the answers are:
A) **Lisa**
B) **35.9 J**
B) To calculate the change in kinetic energy (KE) of the bowling ball, we can use the formula for kinetic energy:
\[
KE = \frac{1}{2} mv^2
\]
where:
- \( m \) is the mass (6 kg for the bowling ball),
- \( v \) is the velocity (converted to meters per second).
1. **Calculate KE at 16 mph (7.1 m/s)**:
\[
KE_{16} = \frac{1}{2} \times 6 \, \text{kg} \times (7.1 \, \text{m/s})^2
\]
\[
KE_{16} = 3 \times 50.41 = 151.23 \, \text{J}
\]
2. **Calculate KE at 14 mph (6.2 m/s)**:
\[
KE_{14} = \frac{1}{2} \times 6 \, \text{kg} \times (6.2 \, \text{m/s})^2
\]
\[
KE_{14} = 3 \times 38.44 = 115.32 \, \text{J}
\]
3. **Find the difference in kinetic energy**:
\[
\Delta KE = KE_{16} - KE_{14}
\]
\[
\Delta KE = 151.23 \, \text{J} - 115.32 \, \text{J} = 35.91 \, \text{J}
\]
The answer rounded to one decimal place is approximately **35.9 J**.
Therefore, the answers are:
A) **Lisa**
B) **35.9 J**