Question
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The figure shown is made of a square and a rectangle.
A composite figure formed from a square and a rectangle. The square has a side length of 4 inches. The rectangle is 2 inches by 5 inches.
What is the area, in square inches, of the figure?
The figure shown is made of a square and a rectangle.
A composite figure formed from a square and a rectangle. The square has a side length of 4 inches. The rectangle is 2 inches by 5 inches.
What is the area, in square inches, of the figure?
Answers
Answered by
GPT-4o mini
To find the area of the composite figure, we need to calculate the areas of the square and the rectangle separately and then add them together.
1. **Area of the Square:**
The area \( A \) of a square is given by the formula:
\[
A = \text{side}^2
\]
In this case, the side length of the square is 4 inches:
\[
A_{\text{square}} = 4^2 = 16 \text{ square inches}
\]
2. **Area of the Rectangle:**
The area \( A \) of a rectangle is given by the formula:
\[
A = \text{length} \times \text{width}
\]
Here, the length is 5 inches and the width is 2 inches:
\[
A_{\text{rectangle}} = 5 \times 2 = 10 \text{ square inches}
\]
3. **Total Area of the Composite Figure:**
Now we add the areas of the square and rectangle together:
\[
A_{\text{total}} = A_{\text{square}} + A_{\text{rectangle}} = 16 + 10 = 26 \text{ square inches}
\]
Therefore, the area of the figure is **26**.
1. **Area of the Square:**
The area \( A \) of a square is given by the formula:
\[
A = \text{side}^2
\]
In this case, the side length of the square is 4 inches:
\[
A_{\text{square}} = 4^2 = 16 \text{ square inches}
\]
2. **Area of the Rectangle:**
The area \( A \) of a rectangle is given by the formula:
\[
A = \text{length} \times \text{width}
\]
Here, the length is 5 inches and the width is 2 inches:
\[
A_{\text{rectangle}} = 5 \times 2 = 10 \text{ square inches}
\]
3. **Total Area of the Composite Figure:**
Now we add the areas of the square and rectangle together:
\[
A_{\text{total}} = A_{\text{square}} + A_{\text{rectangle}} = 16 + 10 = 26 \text{ square inches}
\]
Therefore, the area of the figure is **26**.
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