In the beta decay reaction provided, \( ^{60}_{27}\text{Co} \) (Cobalt-60) decays. In beta decay, a neutron in the nucleus is converted into a proton while releasing a beta particle and an antineutrino. This increases the atomic number by 1 while keeping the mass number the same.
Thus, the decay product of \( ^{60}_{27}\text{Co} \) will have the following properties:
- Mass number: 60 (remains the same)
- Atomic number: 28 (increased by 1)
This results in the formation of \( ^{60}_{28}\text{Ni} \) (Nickel-60).
Therefore, the correct answer is Nickel - 60.