In beta decay, specifically beta-minus decay, a neutron is converted into a proton, and an electron (beta particle) is emitted.
For the decay of \( ^{60}_{27}Co \):
- The atomic number (proton number) increases by 1 (from 27 to 28).
- The mass number remains the same (60).
Therefore, the daughter nuclide produced from the decay will be \( ^{60}_{28}Ni \) (Nickel-60).
Among the options you provided, "Nickel - 60" is the correct response.