Asked by N
Which is a possible daughter nuclide formed in this model of a beta decay reaction? (1 point) 60 on top then 27 co -- 2^0 -1 on bottom b+ 2 0 on top 0 on bottom y +?Responses Nickel - 60 Nickel - 60 Copper - 60 Copper - 60 Iron - 26 Iron - 26 None of these will be formed.
Which is a possible daughter nuclide formed in this model of a beta decay reaction? (1 point) 60 on top then 27 co -- 2^0 -1 on bottom b+ 2 0 on top 0 on bottom y +?Responses Nickel - 60 Nickel - 60 Copper - 60 Copper - 60 Iron - 26 Iron - 26 None of these will be formed.
Which is a possible daughter nuclide formed in this model of a beta decay reaction? (1 point) 60 on top then 27 co -- 2^0 -1 on bottom b+ 2 0 on top 0 on bottom y +?Responses Nickel - 60 Nickel - 60 Copper - 60 Copper - 60 Iron - 26 Iron - 26 None of these will be formed.
Answers
Answered by
GPT-4o mini
In the equation provided, you have a cobalt-60 (\(^{60}_{27}Co\)) nucleus undergoing beta decay (positron emission). The reaction can be represented as follows:
\[
^{60}_{27}Co \rightarrow ^{60}_{26}Ni + \beta^+ + \nu_e
\]
In beta decay, a proton is transformed into a neutron and a positron (\(\beta^+\)) is emitted along with a neutrino (\(\nu_e\)). When cobalt-60 emits a positron, its atomic number decreases by 1, converting it into nickel-60 (\(^{60}_{28}Ni\)).
So, the daughter nuclide formed in this beta decay reaction is:
**Nickel - 60 (\(^{60}_{28}Ni\))**.
Therefore, among the options provided, the correct response is:
- **Nickel - 60**.
\[
^{60}_{27}Co \rightarrow ^{60}_{26}Ni + \beta^+ + \nu_e
\]
In beta decay, a proton is transformed into a neutron and a positron (\(\beta^+\)) is emitted along with a neutrino (\(\nu_e\)). When cobalt-60 emits a positron, its atomic number decreases by 1, converting it into nickel-60 (\(^{60}_{28}Ni\)).
So, the daughter nuclide formed in this beta decay reaction is:
**Nickel - 60 (\(^{60}_{28}Ni\))**.
Therefore, among the options provided, the correct response is:
- **Nickel - 60**.