To determine which statement is true, we need to calculate the kinetic energy of both the car and the bus. The formula for kinetic energy (KE) is given by:
\[ KE = \frac{1}{2} mv^2 \]
where \( m \) is the mass of the object and \( v \) is its velocity.
Since both the car and the bus are traveling at the same speed (60 mph), the difference in their kinetic energy comes from their masses. Typically, a large passenger bus has a greater mass than a small car.
Therefore:
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The kinetic energy of the car (with mass \( m_c \)) is: \[ KE_c = \frac{1}{2} m_c (60 , \text{mph})^2 \]
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The kinetic energy of the bus (with mass \( m_b \)) is: \[ KE_b = \frac{1}{2} m_b (60 , \text{mph})^2 \]
Given that \( m_b > m_c \), we can conclude that:
\[ KE_b > KE_c \]
Thus, the correct statement is: The bus has more kinetic energy than the car.